magnet中怎么画椭圆？

lenovol

不会弄附件，贴出代码，大家复制到文本文档里，然后用magnet运行一下就是椭圆，可以在代码中根据椭圆的尺寸更改，生成自己想要的椭圆
' Ellipse Drawing Script
' The following code will draw an ellipse using Construction Slice lines
'
' Equation of an ellipse: ((x-h)^2)/a^2 + ((y-k)^2)/b^2 = 1
' where
'   (h,k) is the center of the ellipse
'   a is the semi-major axis length
'   b is the semi-minor axis length
'
' Parametric equation is used here
' x=h+a*cos(t)*cos(theta)-b*sin(t)*sin(theta)
' y=k+b*sin(t)*cos(theta)+a*cos(t)*sin(theta)
' where
'   t is the parameter
'   theta=angle of rotation about center, with respect to x-axis


' Constants
h=5        'x-coordinate of center of ellipse
k=7        'y-coordinate of center of ellipse
a=15       'Semi-major axis length
b=8        'Semi-minor axis length
theta=0    'Angle of Rotation (degrees)
nblines=50 'Number of lines to be used in discretization
PI=3.14159265358979323846

'Initialization of parameter
t=0

'Starting point calculation
x1=h+a*cos(t*PI/180)*cos(theta*PI/180)-b*sin(t*PI/180)*sin(theta*PI/180)
y1=k+b*sin(t*PI/180)*cos(theta*PI/180)+a*cos(t*PI/180)*sin(theta*PI/180)

For i = 1 to nblines
       
        t=t+(360/nblines) 't is incremented by 360/nblines for each iteration

        'End point calculation       
        x2=h+a*cos(t*PI/180)*cos(theta*PI/180)-b*sin(t*PI/180)*sin(theta*PI/180)
        y2=k+b*sin(t*PI/180)*cos(theta*PI/180)+a*cos(t*PI/180)*sin(theta*PI/180)
       
        Call getDocument().getView().newLine(x1,y1, x2, y2)
       
        x1=x2
        y1=y2

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YPh632

楼上牛人，膜拜ing~

kkguo

多谢楼主分享，学习了。