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A =
[ (2^(1/2)*3^(1/2)*cos(x))/3, (2^(1/2)*3^(1/2)*cos(x - (2*pi)/3))/3, (2^(1/2)*3^(1/2)*cos((2*pi)/3 + x))/3]
[ -(2^(1/2)*3^(1/2)*sin(x))/3, -(2^(1/2)*3^(1/2)*sin(x - (2*pi)/3))/3, -(2^(1/2)*3^(1/2)*sin((2*pi)/3 + x))/3]
[ 3^(1/2)/3, 3^(1/2)/3, 3^(1/2)/3]
B =
[ L0 + Ls0 + Ls2*cos(2*x), Ls2*cos(2*x - (2*pi)/3) - Ls0/2, Ls2*cos((2*pi)/3 + 2*x) - Ls0/2]
[ Ls2*cos(2*x - (2*pi)/3) - Ls0/2, L0 + Ls0 + Ls2*cos((2*pi)/3 + 2*x), Ls2*cos(2*x) - Ls0/2]
[ Ls2*cos((2*pi)/3 + 2*x) - Ls0/2, Ls2*cos(2*x) - Ls0/2, L0 + Ls0 + Ls2*cos(2*x - (2*pi)/3)]
C =
[ (2^(1/2)*3^(1/2)*cos(x))/3, -(2^(1/2)*3^(1/2)*sin(x))/3, 3^(1/2)/3]
[ (2^(1/2)*3^(1/2)*cos(x - (2*pi)/3))/3, -(2^(1/2)*3^(1/2)*sin(x - (2*pi)/3))/3, 3^(1/2)/3]
[ (2^(1/2)*3^(1/2)*cos((2*pi)/3 + x))/3, -(2^(1/2)*3^(1/2)*sin((2*pi)/3 + x))/3, 3^(1/2)/3]
求A*B*C,按书上的例子这个计算结果是一个斜矩阵,手工算太麻烦了,求高手指点? |
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